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File: 1369133643756.jpQ-f14 KB. 300x300. 220500-kazari_uiharu_large[1].jpg) r Anonymous 05/21/13(Tue)06:54 No.85981043 Replies: »85981199 »85981325 »85883828 What would Uiharu's esper ability be like if she were a higher level? Full thermal control on anything she touches? Immunity to extreme temperatures? Heat vision? T Anonymous 05/21/13(Tue)06:57 No 85981151 She'd work in a cafeteria. A really good one. T Anonymous 05/21/13(Tue)06:57 No 85981156 Super-heated energy swords, perfect barriers, anything she wants, really T Anonymous 05/21/13(Tue)06:59 No 85981197 Heat manipulation 100 posts later... r Anonymous 05/21/13(Tue)09:21 No.85985646 Replies: »85985781 »85986303 »85987739 »85983281 Actually, if JC staff knew jack shit about physics Misaka would have murdered Accelerator long ago Accelerator can control 1st ranked tensors (vectors) but cannot control higher order tensors or 0th ranked tensors (scalars). All Misaka would have to do is create a strong magnetic field and run towards Accelerator. The changing magnetic field would induce a changing electric field and Accelerator cannot change the curl of that field. Misaka could also stand near Accelerator and create a strong electric field. While Accelerator can change vectors, he cannot change the divergence of the electric field Misaka creates (modeling Misaka as a point charge). Even if Accelerator could change the fields divergence, the magnitude would still be the same -- it would kill him 200 posts later... Г Anonymous 05/21/13(Tue)11 47 No.85991314 »85991041 This is a definition (saying a negative К value is hotter than +infinityK). whatever it means means nothing in this context, it's just another scale. Furthermore even if Kelvin could go negative, temperature is not a vector: it is a measure of energy. To have 0 К means to have a vacuum (nothing there, devoid of energy). To have less than 0 К means you have to remove from a vacuum. Which doesn't quite work. Г Anonymous 05/21/13(Tue)11:51 No.85991496 »85990869 Misaka is. but then we go back to what I explained previously: All Misaka has to do is create a time varying magnetic field and run towards accelerator. We can approximate the field using either /С В dl = p0 //X(J + s0 3E/3t) dS or fdl E dl = -d/dt Я1 В dS choose Faraday's for easier math, but both work: Then |E| becomes |E| - [-d/dt JJX В dS / cosO] where J/X В-dS is the strength of Misaka's magnetic field (approx as 50T) at +10T/s and assume she's running orthogonal to accelerator. No matter how great Accelerator is at vector manipulation, the magnitude of |E| will still act -- he'll be shocked no matter how he transforms coordinates. Or. if Misaka could get close enough: £30 E dS = 1/s0 /ЯП edV |E| - 1/eO/£3QdS Я/П edV where ”£3QdS” is the approximate volume of Misaka and e is Misaka's volume charge density.
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а вот про электростатическое поле - вроде да, градиент(скаляр) может привести к тому, что его ударит током.
https://en.wikipedia.org/wiki/Scalar_field
а первый случай с изменяющимся магнитным полем не сработает - т.к. м поле это векторное поле.